What is the axis y=-2/5 x^2+4x ?

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axis y=-2/5 x^2+4x

axis

y = - \frac{2}{5} x^{2} + 4 x

x = 5

Solution steps

y = - \frac{2}{5} x^{2} + 4 x

Rewrite

y = - \frac{2}{5} x^{2} + 4 x

in the standard form

4 (- \frac{5}{8}) (y - 10) = (x - 5)^{2}

Therefore parabola properties are:

(h, k) = (5, 10), p = - \frac{5}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 5

y = - x^{2} - 6 \cdot x + 7

y = x^{2} - 3 x + 5

y = \frac{3}{8} x^{2}

y = - (0.009 (x - 220)^{2} - 220)

(x - 4)^{2} = 8 (y - 3)