What is the axis x^2+20y=0 ?

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axis x^2+20y=0

axis

x^{2} + 20 y = 0

x = 0

Solution steps

x^{2} + 20 y = 0

Rewrite

x^{2} + 20 y = 0

in the standard form:

4 (- 5) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x^{2} = 4 y

y = + x^{2} + 3

y = + (8 - x) (3 x + 2)

y = 4 + 2 x - x^{2}

y = - \frac{2}{5} x^{2} + 4 x