What is the axis y=4x^2-12x+10 ?

The axis y=4x^2-12x+10 is x= 3/2

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axis y=4x^2-12x+10

axis

y = 4 x^{2} - 12 x + 10

x = \frac{3}{2}

Solution steps

y = 4 x^{2} - 12 x + 10

Rewrite

y = 4 x^{2} - 12 x + 10

in the standard form

4 \cdot \frac{1}{16} (y - 1) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, 1), p = \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

y = x^{2} + 3 x + 2

y = (2 x + 5) (x + 6)

y = x^{2} + 3 x + 1

y = x^{2} + x + 1

y = 3 (x - 1)^{2} - 2