What is the axis y=-4x^2+183x-1247 ?

The axis y=-4x^2+183x-1247 is x= 183/8

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axis y=-4x^2+183x-1247

axis

y = - 4 x^{2} + 183 x - 1247

x = \frac{183}{8}

Solution steps

y = - 4 x^{2} + 183 x - 1247

Rewrite

y = - 4 x^{2} + 183 x - 1247

in the standard form

4 (- \frac{1}{16}) (y - \frac{13537}{16}) = (x - \frac{183}{8})^{2}

Therefore parabola properties are:

(h, k) = (\frac{183}{8}, \frac{13537}{16}), p = - \frac{1}{16}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{183}{8}

y^{2} + 8 x + 4 y + 20 = 0

y = - x^{2} + 6 x + 7

12 (x - 2) = (y + 2)^{2}

(y - 2)^{2} = 4 (- 10) (x - 2)

y^{2} = - 2 x