What is the axis y=3(x-1)^2-2 ?

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axis y=3(x-1)^2-2

axis

y = 3 (x - 1)^{2} - 2

x = 1

Solution steps

y = 3 (x - 1)^{2} - 2

Rewrite

y = 3 (x - 1)^{2} - 2

in the standard form:

4 \cdot \frac{1}{12} (y - (- 2)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

x = (y + 1)^{2} + 1

y = - 4 x^{2} + 183 x - 1247

y^{2} + 8 x + 4 y + 20 = 0

y = - x^{2} + 6 x + 7

12 (x - 2) = (y + 2)^{2}