What is the axis y=(5-x)(2x-3) ?

The axis y=(5-x)(2x-3) is x= 13/4

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axis y=(5-x)(2x-3)

axis

y = (5 - x) (2 x - 3)

x = \frac{13}{4}

Solution steps

y = (5 - x) (2 x - 3)

Rewrite

y = (5 - x) (2 x - 3)

in the standard form

4 (- \frac{1}{8}) (y - \frac{49}{8}) = (x - \frac{13}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{13}{4}, \frac{49}{8}), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{13}{4}

y = 3 x^{2} - 15 x + 6

x^{2} = - 16 y

y = 6 x^{2} - 12 x

y = + x^{2} + 3 x + 14

4 x^{2} - 12 x - 16 y + 41 = 0