What is the axis x=(y-12)^2-156 ?

The axis x=(y-12)^2-156 is y=12

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axis x=(y-12)^2-156

axis

x = (y - 12)^{2} - 156

y = 12

Solution steps

x = (y - 12)^{2} - 156

Rewrite

x = (y - 12)^{2} - 156

in the standard form:

4 \cdot \frac{1}{4} (x - (- 156)) = (y - 12)^{2}

Therefore parabola properties are:

(h, k) = (- 156, 12), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 12

x = \frac{1}{4} y^{2}

y = 3 x^{2} - 2 x + 2

\frac{y - 2}{4} - \frac{x ^{2}}{9} = 1

y = 2 x^{2} + 24 x - 6

y = (2 x)^{2}