What is the axis y=3x^2-15x+6 ?

The axis y=3x^2-15x+6 is x= 5/2

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axis y=3x^2-15x+6

axis

y = 3 x^{2} - 15 x + 6

x = \frac{5}{2}

Solution steps

y = 3 x^{2} - 15 x + 6

Rewrite

y = 3 x^{2} - 15 x + 6

in the standard form

4 \cdot \frac{1}{12} (y - (- \frac{51}{4})) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, - \frac{51}{4}), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{2}

x^{2} = - 16 y

y = 6 x^{2} - 12 x

y = + x^{2} + 3 x + 14

4 x^{2} - 12 x - 16 y + 41 = 0

x = (y - 12)^{2} - 156