What is the axis y=-x^2-8 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=-x^2-8

axis

y = - x^{2} - 8

x = 0

Solution steps

y = - x^{2} - 8

Rewrite

y = - x^{2} - 8

in the standard form:

4 (- \frac{1}{4}) (y - (- 8)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 8), p = - \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = (2 x + 3)^{2}

y = - \frac{1}{4} (x + 9)^{2} - 7

y = - x^{2} - 8 x - 8

y^{2} = 5 x + 3

(y + 4)^{2} = 7 (x - 2)