What is the axis x=y^2-4 ?

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axis x=y^2-4

axis

x = y^{2} - 4

y = 0

Solution steps

x = y^{2} - 4

Rewrite

x = y^{2} - 4

in the standard form:

4 \cdot \frac{1}{4} (x - (- 4)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 0), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = \frac{2}{3} (x - 1)^{2}

x = y^{2} - 1

y = x^{2} - 8 x + 5

y = - (x - 6)^{2} + 1

y = \frac{3}{2} x^{2}