What is the axis 4x^2-1/2 x^2+8x-2y=-2 ?

The axis 4x^2-1/2 x^2+8x-2y=-2 is x=-8/7

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axis 4x^2-1/2 x^2+8x-2y=-2

axis

x = - \frac{8}{7}

Solution steps

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

Rewrite

4 x^{2} - \frac{1}{2} x^{2} + 8 x - 2 y = - 2

in the standard form

4 \cdot \frac{1}{7} (y - (- \frac{9}{7})) = (x - (- \frac{8}{7}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{8}{7}, - \frac{9}{7}), p = \frac{1}{7}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{8}{7}

What is the axis 4x^2-1/2 x^2+8x-2y=-2 ?
The axis 4x^2-1/2 x^2+8x-2y=-2 is x=-8/7