What is the axis y=-1/4 (x+9)^2-7 ?

The axis y=-1/4 (x+9)^2-7 is x=-9

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axis y=-1/4 (x+9)^2-7

axis

y = - \frac{1}{4} (x + 9)^{2} - 7

x = - 9

Solution steps

y = - \frac{1}{4} (x + 9)^{2} - 7

Rewrite

y = - \frac{1}{4} (x + 9)^{2} - 7

in the standard form:

4 (- 1) (y - (- 7)) = (x - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (- 9, - 7), p = - 1

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 9

y = - x^{2} - 8 x - 8

y^{2} = 5 x + 3

(y + 4)^{2} = 7 (x - 2)

y = 6 x^{2} + 3 x

y = 4 x - 3 x^{2}