What is the axis y=(x+1)(2x+5) ?

The axis y=(x+1)(2x+5) is x=-7/4

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axis y=(x+1)(2x+5)

axis

y = (x + 1) (2 x + 5)

x = - \frac{7}{4}

Solution steps

y = (x + 1) (2 x + 5)

Rewrite

y = (x + 1) (2 x + 5)

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{9}{8})) = (x - (- \frac{7}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{7}{4}, - \frac{9}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{7}{4}

y = \frac{1}{4} x^{2} - 3 x - 7

y = 49 x^{2} - 64

y = 3 x^{2} - 3 x + 2

(x - 2)^{2} = - (y - 4)

y = x^{2} + 4 x + 10