What is the axis y=3x^2-3x+2 ?

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axis y=3x^2-3x+2

axis

y = 3 x^{2} - 3 x + 2

x = \frac{1}{2}

Solution steps

y = 3 x^{2} - 3 x + 2

Rewrite

y = 3 x^{2} - 3 x + 2

in the standard form

4 \cdot \frac{1}{12} (y - \frac{5}{4}) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{5}{4}), p = \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{1}{2}

(x - 2)^{2} = - (y - 4)

y = x^{2} + 4 x + 10

y = - 2 x^{2} - 12 x - 23

y = x^{2} + 5 x - 84

y = x^{2} - 4 x + 2