What is the axis y= 1/4 x^2-3x-7 ?

The axis y= 1/4 x^2-3x-7 is x=6

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axis y= 1/4 x^2-3x-7

axis

y = \frac{1}{4} x^{2} - 3 x - 7

x = 6

Solution steps

y = \frac{1}{4} x^{2} - 3 x - 7

Rewrite

y = \frac{1}{4} x^{2} - 3 x - 7

in the standard form

4 \cdot 1 \cdot (y - (- 16)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 16), p = 1

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 6

y = 49 x^{2} - 64

y = 3 x^{2} - 3 x + 2

(x - 2)^{2} = - (y - 4)

y = x^{2} + 4 x + 10

y = - 2 x^{2} - 12 x - 23