What is the axis y=-3x^2-2 ?

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axis y=-3x^2-2

axis

x = 0

Solution steps

y = - 3 x^{2} - 2

Rewrite

y = - 3 x^{2} - 2

in the standard form:

4 (- \frac{1}{12}) (y - (- 2)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 2), p = - \frac{1}{12}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0