What is the axis y=36x-9x^2 ?

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axis y=36x-9x^2

axis

y = 36 x - 9 x^{2}

x = 2

Solution steps

y = 36 x - 9 x^{2}

Rewrite

y = 36 x - 9 x^{2}

in the standard form

4 (- \frac{1}{36}) (y - 36) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 36), p = - \frac{1}{36}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = 5 x^{2} - 8 x + 3

y = x^{2} - 9

x = (2 y - 1) (5 y - 6)

y^{2} + 4 x - 8 y + 12 = 0

y = 2 x^{2} - x - 6