What is the axis y=8x^2+22x-13 ?

The axis y=8x^2+22x-13 is x=-11/8

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axis y=8x^2+22x-13

axis

y = 8 x^{2} + 22 x - 13

x = - \frac{11}{8}

Solution steps

y = 8 x^{2} + 22 x - 13

Rewrite

y = 8 x^{2} + 22 x - 13

in the standard form

4 \cdot \frac{1}{32} (y - (- \frac{225}{8})) = (x - (- \frac{11}{8}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{11}{8}, - \frac{225}{8}), p = \frac{1}{32}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{11}{8}

y = \frac{( x + 7 ) ^{2}}{9}

y = + 4 x^{2} + 7

y = x^{2} + 5 x + 6

y = x^{2} + 5 x + 4

y = x^{2} + 7 x - 30