What is the axis y=x^2-9 ?

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axis y=x^2-9

axis

y = x^{2} - 9

x = 0

Solution steps

y = x^{2} - 9

Rewrite

y = x^{2} - 9

in the standard form:

4 \cdot \frac{1}{4} (y - (- 9)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 9), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

x = (2 y - 1) (5 y - 6)

y^{2} + 4 x - 8 y + 12 = 0

y = 2 x^{2} - x - 6

y = 8 x^{2} + 22 x - 13

y = \frac{( x + 7 ) ^{2}}{9}