What is the axis y=2x^2+9x-3 ?

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axis y=2x^2+9x-3

axis

y = 2 x^{2} + 9 x - 3

x = - \frac{9}{4}

Solution steps

y = 2 x^{2} + 9 x - 3

Rewrite

y = 2 x^{2} + 9 x - 3

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{105}{8})) = (x - (- \frac{9}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{4}, - \frac{105}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{9}{4}

y = 36 x - 9 x^{2}

y = 5 x^{2} - 8 x + 3

y = x^{2} - 9

x = (2 y - 1) (5 y - 6)

y^{2} + 4 x - 8 y + 12 = 0