What is the axis x=2y^2-1-(5y-6) ?

The axis x=2y^2-1-(5y-6) is y= 5/4

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axis x=2y^2-1-(5y-6)

axis

x = 2 y^{2} - 1 - (5 y - 6)

y = \frac{5}{4}

Solution steps

x = 2 y^{2} - 1 - (5 y - 6)

Rewrite

x = 2 y^{2} - 1 - (5 y - 6)

in the standard form

4 \cdot \frac{1}{8} (x - \frac{15}{8}) = (y - \frac{5}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{15}{8}, \frac{5}{4}), p = \frac{1}{8}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = \frac{5}{4}

y = \frac{x ( 3 x - 1 )}{2}

y = + 2 (x + 1)^{2} - 3

y = \frac{x ^{2} - 4 x}{11}

\frac{a + 1}{b} = \frac{a - 1}{b} + \frac{b + 1}{a}

y^{2} - 8 y + 4 x = 0