What is the axis y=(x^2-4x)/(11) ?

The axis y=(x^2-4x)/(11) is x=2

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axis y=(x^2-4x)/(11)

axis

y = \frac{x ^{2} - 4 x}{11}

x = 2

Solution steps

y = \frac{x ^{2} - 4 x}{11}

Rewrite

y = \frac{x ^{2} - 4 x}{11}

in the standard form

4 \cdot \frac{11}{4} (y - (- \frac{4}{11})) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - \frac{4}{11}), p = \frac{11}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

\frac{a + 1}{b} = \frac{a - 1}{b} + \frac{b + 1}{a}

y^{2} - 8 y + 4 x = 0

y = 3 x^{2} + 2 x - 1

y = 2 x^{2} + 20 x + 53

y = x^{2} + 2 x + 7