What is the axis y=(x(3x-1))/2 ?

The axis y=(x(3x-1))/2 is x= 1/6

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axis y=(x(3x-1))/2

axis

y = \frac{x ( 3 x - 1 )}{2}

x = \frac{1}{6}

Solution steps

y = \frac{x ( 3 x - 1 )}{2}

Rewrite

y = \frac{x ( 3 x - 1 )}{2}

in the standard form

4 \cdot \frac{1}{6} (y - (- \frac{1}{24})) = (x - \frac{1}{6})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{6}, - \frac{1}{24}), p = \frac{1}{6}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{1}{6}

y = + 2 (x + 1)^{2} - 3

y = \frac{x ^{2} - 4 x}{11}

\frac{a + 1}{b} = \frac{a - 1}{b} + \frac{b + 1}{a}

y^{2} - 8 y + 4 x = 0

y = 3 x^{2} + 2 x - 1