What is the axis 2x-y^2=0 ?

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axis 2x-y^2=0

axis

2 x - y^{2} = 0

y = 0

Solution steps

2 x - y^{2} = 0

Rewrite

2 x - y^{2} = 0

in the standard form:

4 \cdot \frac{1}{2} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{2}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 0

y = + 6 x^{2} + 12 x

y^{2} + 6 y + 8 x + 25 = 0

y = 5 x^{2} + 1

y = 2 x^{2} - 4 x - 5

x^{2} = 24 y