What is the axis y^2+6y+8x+25=0 ?

The axis y^2+6y+8x+25=0 is y=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y^2+6y+8x+25=0

axis

y^{2} + 6 y + 8 x + 25 = 0

y = - 3

Solution steps

y^{2} + 6 y + 8 x + 25 = 0

Rewrite

y^{2} + 6 y + 8 x + 25 = 0

in the standard form

4 (- 2) (x - (- 2)) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 3), p = - 2

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 3

y = 5 x^{2} + 1

y = 2 x^{2} - 4 x - 5

x^{2} = 24 y

y = + 3 x^{2} + 6 x

y = x^{2} - 6 x + 1