What is the axis y=x^2-6x+1 ?

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axis y=x^2-6x+1

axis

y = x^{2} - 6 x + 1

x = 3

Solution steps

y = x^{2} - 6 x + 1

Rewrite

y = x^{2} - 6 x + 1

in the standard form

4 \cdot \frac{1}{4} (y - (- 8)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 8), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 3

y = (x + 314)^{2}

y = - 2 x^{2}

y = \frac{x ^{3}}{x}

f (x) = x^{2} - 4 x

y = \frac{- 3 x ^{2} - 2 x + 6}{5}