What is the axis f(x)=x^2-4x ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis f(x)=x^2-4x

axis

f (x) = x^{2} - 4 x

x = 2

Solution steps

y = x^{2} - 4 x

Rewrite

y = x^{2} - 4 x

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = \frac{- 3 x ^{2} - 2 x + 6}{5}

y = x^{2} + 2 x + 4

y = 2 x^{2} - 6

y = 8 - 5 x + x^{2}

y = 5 x^{2} - 7