What is the axis y=(x-6)^2-9 ?

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axis y=(x-6)^2-9

axis

y = (x - 6)^{2} - 9

x = 6

Solution steps

y = (x - 6)^{2} - 9

Rewrite

y = (x - 6)^{2} - 9

in the standard form:

4 \cdot \frac{1}{4} (y - (- 9)) = (x - 6)^{2}

Therefore parabola properties are:

(h, k) = (6, - 9), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 6

y^{2} - 12 x + 8 y + 88 = 0

y = + x^{2} - 7

y = \frac{1}{4} x^{2} - 3

2 x - y^{2} = 0

y = + 6 x^{2} + 12 x