What is the axis y=-0.1x^2+0.8x+98.8 ?

The axis y=-0.1x^2+0.8x+98.8 is x=4

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axis y=-0.1x^2+0.8x+98.8

axis

y = - 0.1 x^{2} + 0.8 x + 98.8

x = 4

Solution steps

y = - 0.1 x^{2} + 0.8 x + 98.8

Rewrite

y = - 0.1 x^{2} + 0.8 x + 98.8

in the standard form

4 (- 2.5) (y - 100.4) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 100.4), p = - 2.5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 4

y = x^{2} - 4 x - 5

y = \frac{1}{2} (x - 3)^{2} + 4

y = \frac{x ^{4} - 1}{x ^{2} - 1}

y = 64 x^{2}

y = 2.5 + 2.2 x - 0.6 x^{2}