What is the axis y=(x^4-1)/(x^2-1) ?

The axis y=(x^4-1)/(x^2-1) is x=0

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axis y=(x^4-1)/(x^2-1)

axis

y = \frac{x ^{4} - 1}{x ^{2} - 1}

x = 0

Solution steps

y = \frac{x ^{4} - 1}{x ^{2} - 1}

Rewrite

y = \frac{x ^{4} - 1}{x ^{2} - 1}

in the standard form

4 \cdot \frac{1}{4} (y - 1) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 1), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 64 x^{2}

y = 2.5 + 2.2 x - 0.6 x^{2}

x^{2} = - 14 (y + 1)

x = - 8 y^{2}

(x + 3)^{2} = 16 (y - 9)