What is the axis y=64x^2 ?

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axis y=64x^2

axis

y = 64 x^{2}

x = 0

Solution steps

y = 64 x^{2}

Rewrite

y = 64 x^{2}

in the standard form:

4 \cdot \frac{1}{256} (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{256}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2.5 + 2.2 x - 0.6 x^{2}

x^{2} = - 14 (y + 1)

x = - 8 y^{2}

(x + 3)^{2} = 16 (y - 9)

y = - 0.1 x^{2} + 1.4 x + 98.4