What is the vertices y=x^2-24x-12 ?

The vertices y=x^2-24x-12 is Minimum (12,-156)

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vertices y=x^2-24x-12

vertices

y = x^{2} - 24 x - 12

Minimum (12, - 156)

Solution steps

y = x^{2} - 24 x - 12

The parabola parameters are:

a = 1, b = - 24, c = - 12

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 24 )}{2 \cdot 1}

Simplify

x_{v} = 12

Plug in

x_{v} = 12

to find the

y_{v}

value

y_{v} = - 156

Therefore the parabola vertex is

(12, - 156)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (12, - 156)

x = 4 y^{2}

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

y^{2} = - 6 x

y^{2} - 4 x + 4 y - 4 = 0

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

What is the vertices y=x^2-24x-12 ?
The vertices y=x^2-24x-12 is Minimum (12,-156)