What is y^2-4x+4y-4=0 ?

The solution to y^2-4x+4y-4=0 is Parabola with (h,k)=(-2,-2),p=1

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y^2-4x+4y-4=0

y^{2} - 4 x + 4 y - 4 = 0

(h, k) = (- 2, - 2), p = 1

Solution steps

y^{2} - 4 x + 4 y - 4 = 0

Rewrite

y^{2} - 4 x + 4 y - 4 = 0

in the standard form

4 \cdot 1 \cdot (x - (- 2)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, - 2), p = 1

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

16 x^{2} + 25 y^{2} = 400

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

9 x^{2} - 4 y^{2} = 36

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

What is y^2-4x+4y-4=0 ?
The solution to y^2-4x+4y-4=0 is Parabola with (h,k)=(-2,-2),p=1