What is 16x^2+25y^2=400 ?

The solution to 16x^2+25y^2=400 is Ellipse with (h,k)=(0,0),a=5,b=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16x^2+25y^2=400

16 x^{2} + 25 y^{2} = 400

(h, k) = (0, 0), a = 5, b = 4

Solution steps

16 x^{2} + 25 y^{2} = 400

Rewrite

16 x^{2} + 25 y^{2} = 400

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 5, b = 4

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

9 x^{2} - 4 y^{2} = 36

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

x^{2} - y^{2} = 3

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

What is 16x^2+25y^2=400 ?
The solution to 16x^2+25y^2=400 is Ellipse with (h,k)=(0,0),a=5,b=4