What is the vertices 9x^2-4y^2=36 ?

The vertices 9x^2-4y^2=36 is (2,0),(-2,0)

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vertices 9x^2-4y^2=36

vertices

9 x^{2} - 4 y^{2} = 36

(2, 0), (- 2, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

9 x^{2} - 4 y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 3

(0 + 2, 0), (0 - 2, 0)

Refine

(2, 0), (- 2, 0)

\frac{x ^{2}}{4} - \frac{y ^{2}}{16} = 1

x^{2} - y^{2} = 3

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

x^{2} + 16 y^{2} = 16

f (x) = x^{2} - 2 x + 1