What is x^2+16y^2=16 ?

The solution to x^2+16y^2=16 is Ellipse with (h,k)=(0,0),a=4,b=1

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x^2+16y^2=16

x^{2} + 16 y^{2} = 16

(h, k) = (0, 0), a = 4, b = 1

Solution steps

x^{2} + 16 y^{2} = 16

Rewrite

x^{2} + 16 y^{2} = 16

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 1

f (x) = x^{2} - 2 x + 1

y^{2} = - 10 x

f (x) = x^{2} - 6 x + 5

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

x^{2} + y = 1

What is x^2+16y^2=16 ?
The solution to x^2+16y^2=16 is Ellipse with (h,k)=(0,0),a=4,b=1