What is (x^2}{16}+\frac{y^2)/7 =1 ?

The solution to (x^2}{16}+\frac{y^2)/7 =1 is Ellipse with (h,k)=(0,0),a=4,b=sqrt(7)

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(x^2}{16}+\frac{y^2)/7 =1

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

(h, k) = (0, 0), a = 4, b = 7

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{7} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 7

x^{2} + y = 1

x = y^{2} - 3

x^{2} - y^{2} = 49

\frac{y ^{2}}{49} - \frac{x ^{2}}{25} = 1

9 x^{2} - 4 y^{2} - 72 x = 0

What is (x^2}{16}+\frac{y^2)/7 =1 ?
The solution to (x^2}{16}+\frac{y^2)/7 =1 is Ellipse with (h,k)=(0,0),a=4,b=sqrt(7)