What is the foci (y^2)/(49)-(x^2)/(25)=1 ?

The foci (y^2)/(49)-(x^2)/(25)=1 is (0,sqrt(74)),(0,-sqrt(74))

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foci (y^2)/(49)-(x^2)/(25)=1

foci

\frac{y ^{2}}{49} - \frac{x ^{2}}{25} = 1

(0, 74), (0, - 74)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{49} - \frac{x ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 7, b = 5

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 7^{2} + 5^{2} : 74

(0, 0 + 74), (0, 0 - 74)

Refine

(0, 74), (0, - 74)

9 x^{2} - 4 y^{2} - 72 x = 0

x^{2} + y^{2} + 6 x + 2 y + 6 = 0

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

4 x^{2} - y^{2} = 16

x^{2} + 2 y^{2} - 2 x + 8 y + 5 = 0

What is the foci (y^2)/(49)-(x^2)/(25)=1 ?
The foci (y^2)/(49)-(x^2)/(25)=1 is (0,sqrt(74)),(0,-sqrt(74))