What is (x^2)/(36)+(y^2)/(49)=1 ?

The solution to (x^2)/(36)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=6,b=7

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(x^2)/(36)+(y^2)/(49)=1

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 6, b = 7

Solution steps

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 6

y^{2} = - 6 x

y^{2} - 4 x + 4 y - 4 = 0

\frac{x ^{2}}{49} - \frac{y ^{2}}{16} = 1

16 x^{2} + 25 y^{2} = 400

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

What is (x^2)/(36)+(y^2)/(49)=1 ?
The solution to (x^2)/(36)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=6,b=7