What is the directrix x^2 ?

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directrix x^2

directrix

x^{2}

y = - \frac{1}{4}

Solution steps

Rewrite

y = x^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{4}

Parabola is symmetric around the y-axis and so the directrix is a line parallel to the x-axis, a distance

- p

from the center

(0, 0)

y-coordinate

y = 0 - p

y = 0 - \frac{1}{4}

Refine

y = - \frac{1}{4}

\frac{x ^{2}}{36} + \frac{y ^{2}}{9} = 1

x^{2} - 4 y = 0

\frac{( x - 4 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{9} = 1

x^{2} = 4 y - 2 y^{2}

x = (y - 5)^{2}