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Popular >

foci (y-2)^2=2x+1

Solution

foci

(y - 2)^{2} = 2 x + 1

Solution

(0, 2)

Solution steps

Rewrite

(y - 2)^{2} = 2 x + 1

in the standard form:

4 \cdot \frac{1}{2} (x - (- \frac{1}{2})) = (y - 2)^{2}

(h, k) = (- \frac{1}{2}, 2), p = \frac{1}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(- \frac{1}{2}, 2)

along the x-axis

(- \frac{1}{2} + p, 2)

= (- \frac{1}{2} + \frac{1}{2}, 2)

Refine

(0, 2)

Popular Examples

foci x^2-4x+3 foci

x^{2} - 4 x + 3

foci (x-4)^2=-12(y-3)foci

(x - 4)^{2} = - 12 (y - 3)

foci x^2-2x-24 foci

x^{2} - 2 x - 24

foci X^2-5X-24 foci

X^{2} - 5 X - 24

foci (x-3)^2=12(y-2)foci

(x - 3)^{2} = 12 (y - 2)

Frequently Asked Questions (FAQ)

What is the foci (y-2)^2=2x+1 ?
The foci (y-2)^2=2x+1 is (0,2)