What is the foci (x-3)^2=12(y-2) ?

The foci (x-3)^2=12(y-2) is (3,5)

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foci (x-3)^2=12(y-2)

foci

(x - 3)^{2} = 12 (y - 2)

(3, 5)

Solution steps

Rewrite

(x - 3)^{2} = 12 (y - 2)

in the standard form:

4 \cdot 3 (y - 2) = (x - 3)^{2}

(h, k) = (3, 2), p = 3

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(3, 2)

along the y-axis

(3, 2 + p)

= (3, 2 + 3)

Refine

(3, 5)

(x - 102.05) \frac{498.625 - x}{0.1249}

x^{2} + 9 x + 18

x = 6 y^{2}

2250 (0.015 - 0.001 x)^{2} + 6000 x

x^{2} \cdot 3