What is the foci 2250(0.015-0.001x)^2+6000x ?

The foci 2250(0.015-0.001x)^2+6000x is (-1333318.33333…,111.11111…)

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foci 2250(0.015-0.001x)^2+6000x

foci

(- 1333318.33333 \dots, 111.11111 \dots)

Solution steps

Rewrite

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

in the standard form

4 \cdot 111.11111 \dots (y - 0) = (x - (- \frac{5999.9325}{0.0045}))^{2}

(h, k) = (- \frac{5999.9325}{0.0045}, 0), p = 111.11111 \dots

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{5999.9325}{0.0045}, 0)

along the y-axis

(- \frac{5999.9325}{0.0045}, 0 + p)

= (- \frac{5999.9325}{0.0045}, 0 + 111.11111 \dots)

Refine

(- 1333318.33333 \dots, 111.11111 \dots)

What is the foci 2250(0.015-0.001x)^2+6000x ?
The foci 2250(0.015-0.001x)^2+6000x is (-1333318.33333…,111.11111…)