What is the foci y^2=-6(x-3) ?

The foci y^2=-6(x-3) is (3/2 ,0)

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foci y^2=-6(x-3)

foci

y^{2} = - 6 (x - 3)

(\frac{3}{2}, 0)

Solution steps

Rewrite

y^{2} = - 6 (x - 3)

in the standard form:

4 (- \frac{3}{2}) (x - 3) = (y - 0)^{2}

(h, k) = (3, 0), p = - \frac{3}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(3, 0)

along the x-axis

(3 + p, 0)

= (3 + (- \frac{3}{2}), 0)

Refine

(\frac{3}{2}, 0)

y = x^{2} + 7 x - 1

+ 3 y^{2} = 24 x

y = \frac{18 x ^{6}}{27 x ^{4}}

y^{2} - 2 y - 8 x - 39 = 0

- 2 x^{2} + 20 x - y - 52 = 0