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Beliebt Geometry >

foki-2x^2+20x-y-52=0

Lösung

foki

- 2 x^{2} + 20 x - y - 52 = 0

Lösung

(5, - \frac{17}{8})

Schritte zur Lösung

Rewrite

- 2 x^{2} + 20 x - y - 52 = 0

in the standard form

4 (- \frac{1}{8}) (y - (- 2)) = (x - 5)^{2}

(h, k) = (5, - 2), p = - \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(5, - 2)

along the y-axis

(5, - 2 + p)

= (5, - 2 + (- \frac{1}{8}))

Fasse zusammen

(5, - \frac{17}{8})

Graph

Beliebte Beispiele

f oc i x^{2} + 20 y = 0

foki-0.3x^2+2x+3

f oc i - 0.3 x^{2} + 2 x + 3

f oc i x^{2} - 5 x + 3

foki y=x^2+2x-3

f oc i y = x^{2} + 2 x - 3

foki y=5x^2-15x

f oc i y = 5 x^{2} - 15 x