9y^2-16x^2-256=0

解

9 y^{2} - 16 x^{2} - 256 = 0

(h, k) = (0, 0), a = \frac{16}{3}, b = 4

解答ステップ

9 y^{2} - 16 x^{2} - 256 = 0

9 y^{2} - 16 x^{2} - 256 = 0

を標準的な双曲線のequationで書き換える

\frac{( y - 0 ) ^{2}}{( \frac{16}{3} ) ^{2}} - \frac{( x - 0 ) ^{2}}{4 ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (0, 0), a = \frac{16}{3}, b = 4