What is the directrix x=-1/12 y^2 ?

The directrix x=-1/12 y^2 is x=3

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directrix x=-1/12 y^2

directrix

x = - \frac{1}{12} y^{2}

x = 3

Solution steps

Rewrite

x = - \frac{1}{12} y^{2}

in the standard form:

4 (- 3) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 3

Parabola is symmetric around the x-axis and so the directrix is a line parallel to the y-axis, a distance

- p

from the center

(0, 0)

x-coordinate

x = 0 - p

x = 0 - (- 3)

Refine

x = 3

4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

x^{2}

y^{2} = - 12 x

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0