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Popular >

foci y^2=-12x

Solution

foci

y^{2} = - 12 x

Solution

(- 3, 0)

Solution steps

Rewrite

y^{2} = - 12 x

in the standard form:

4 (- 3) (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = - 3

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + (- 3), 0)

Refine

(- 3, 0)

Popular Examples

9x^2-y^2-36x-6y+18=0

9 x^{2} - y^{2} - 36 x - 6 y + 18 = 0

9 y^{2} - 16 x^{2} = 144

(x - 1)^{2} + y^{2} = 1

foci 16x^2+25y^2=400 foci

16 x^{2} + 25 y^{2} = 400

vertices (x^2)/(25)+(y^2)/(16)=1 vertices

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

Frequently Asked Questions (FAQ)

What is the foci y^2=-12x ?
The foci y^2=-12x is (-3,0)