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Popular >

foci 16x^2+25y^2=400

Solution

foci

16 x^{2} + 25 y^{2} = 400

Solution

(3, 0), (- 3, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

16 x^{2} + 25 y^{2} = 400 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} - 4^{2} : 3

(0 + 3, 0), (0 - 3, 0)

Refine

(3, 0), (- 3, 0)

Popular Examples

vertices (x^2)/(25)+(y^2)/(16)=1 vertices

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

4 \leq - x^{2} - y

18x^2-64x-14y+150=0

18 x^{2} - 64 x - 14 y + 150 = 0

x^2+y^2+6x-4y-12=0

x^{2} + y^{2} + 6 x - 4 y - 12 = 0

eccentricity 36x^2+y^2=36 eccentricity

36 x^{2} + y^{2} = 36

Frequently Asked Questions (FAQ)

What is the foci 16x^2+25y^2=400 ?
The foci 16x^2+25y^2=400 is (3,0),(-3,0)