What is -x^2-6x+y-8=0 ?

The solution to -x^2-6x+y-8=0 is Parabola with (h,k)=(-3,-1),p= 1/4

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-x^2-6x+y-8=0

- x^{2} - 6 x + y - 8 = 0

(h, k) = (- 3, - 1), p = \frac{1}{4}

Solution steps

- x^{2} - 6 x + y - 8 = 0

Rewrite

- x^{2} - 6 x + y - 8 = 0

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, - 1), p = \frac{1}{4}

x^{2} + y^{2} - 2 x + 4 y - 4 = 0

x = - \frac{1}{12} y^{2}

4 x^{2} + 9 y^{2} - 16 x + 18 y = 11

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

x^{2}

What is -x^2-6x+y-8=0 ?
The solution to -x^2-6x+y-8=0 is Parabola with (h,k)=(-3,-1),p= 1/4